Hello friends,
If father -> Grey{SF} and Mother = Green then outcome?
If father -> Grey{DF} and Mother = Green then outcome?
I have question that grey and green comes under what mutation recessive or something else.
pairing outcome help please
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Re: pairing outcome help please
i ask very simple question, no one knows the answer? please help me out and give me detail.
Re: pairing outcome help please
Blovekhi,
Let's assume the green hen is not carrying the blue gene. Your first pairing will result in 50% green/blue cocks and hens and 50% greygreens/blue cocks and hens.
The second pairing will result in all grey green/ blue offspring.
Let's assume the green hen is not carrying the blue gene. Your first pairing will result in 50% green/blue cocks and hens and 50% greygreens/blue cocks and hens.
The second pairing will result in all grey green/ blue offspring.
Re: pairing outcome help please
Hi Blovekhi
Further to help you on your query a grey gene acts as "autosomal dominant".
Detailed descriptions are below :-
Autosomal - locus of the mutation gene is not at sex chromosome. X or Y
Dominant - mutation gene can overrule the second from the pair, so the presence of only one mutated gene is sufficient for the mutation to express. According to the number of mutation genes single factor(sf) and double factor(df) birds can be distingush. Visually, they look the same the only difference is in inheritance.
In order to produce a mutated bird, it is sufficient to have at least one single factor parent. Let's assign (sf) to the single factor bird, (df) to the double factor bird, and xx to a normal one. Then the mutated bird can be produced from the following matings:
(df) x (df) = 100% (df)
(df) x (sf) = 50% (df) 50% (sf)
(df) x xx = 100% (sf)
(sf) x (sf) = 25% (df) 50% (sf) 25% xx
(sf) x xx = 50% (sf) 50% xx
The sex of the parents is irrelevant.
Further to help you on your query a grey gene acts as "autosomal dominant".
Detailed descriptions are below :-
Autosomal - locus of the mutation gene is not at sex chromosome. X or Y
Dominant - mutation gene can overrule the second from the pair, so the presence of only one mutated gene is sufficient for the mutation to express. According to the number of mutation genes single factor(sf) and double factor(df) birds can be distingush. Visually, they look the same the only difference is in inheritance.
In order to produce a mutated bird, it is sufficient to have at least one single factor parent. Let's assign (sf) to the single factor bird, (df) to the double factor bird, and xx to a normal one. Then the mutated bird can be produced from the following matings:
(df) x (df) = 100% (df)
(df) x (sf) = 50% (df) 50% (sf)
(df) x xx = 100% (sf)
(sf) x (sf) = 25% (df) 50% (sf) 25% xx
(sf) x xx = 50% (sf) 50% xx
The sex of the parents is irrelevant.
Re: pairing outcome help please
Thanks everyone helping me out.